Seymour, IA has a population of 656 and is the 17,855th largest city in the United States. The population density is 280 per sq mi which is 412% higher than the Iowa average and 209% higher than the national average. The median age in Seymour is 51 which is approximately 33% higher than the Iowa average of 38. In Seymour, 65% of the population over 15 years of age are married, 99% speak English and 0% speak Spanish. 77% of Seymour residents were born in Iowa, 22% were born out of state, 0% were born outside of the United States and 1% were foreign born.
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The population density in Seymour is 412% higher than Iowa.
The median age in Seymour is 33% higher than Iowa.
In Seymour 97.10% of the population is White.
In Seymour 1.83% of the population is Black or African American.